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A Multiple Part Puzzle
Last month's puzzle gave you a game in progress, where X and O
had filled the board with spooky marks, leaving three entanglements and
a situation whose outcome is yet to be decided; your challenge was
to answer five questions and thus evaluate X's position
and find his best and worst scenarios.
Question 1 is actually easy to answer.
There are three entanglements on the board, each entangling two moves.
A two-move entanglement can be collapsed in any of three ways;
thus X has 3 × 3 = 9 ways to cause an entanglement on move 7.
Question 2 is a bit tedious, but it can be answered by examining the 36 classical
ensembles resulting from the 36 possible moves X has.
It turns out that
in 21 of those ensembles O has already won one classical game,
in 14 of remaining ensembles O has two-in-a-row in one or more games,
and only one ensemble has no possible win for O.
That ensemble results from X marking squares 3 and 5 on move 7.
Question 3 asks whether X can keep O from winning without
making a cyclic entanglement. On move 7, X has 27 possibilities
that do not make an entanglement, but all of those leave O with a possible
win, so X certainly cannot do this on move 7.
X's next move will be move 9, and all his moves will certainly make a cycle.
So the answer to this question appears to be, No.
Question 4 asks if X can force a win.
The answer appears to be that X cannot.
His best choice for move 7 (squares 3 and 5) leave him with two games in the ensemble
with two marks in a row; O can easily block both of them by placing her
next move in squares 1 and 2. X can still try for a win in row 2,
but that can happen only if O makes the wrong choice in the final collapse.
Question 5 asks if X can give the game away.
Given the number of possible wins O has in the various classical ensembles,
it certainly appears that he can, if he is not careful.
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