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Doom?
In a classical tic-tac-toe game, if X gets marks in
three corners, it's all over. He has three ways to make three
in a row (across, down, and the diagonal) and if O doesn't
already have two of them blocked, she's doomed.
This is not necessarily the case in Quantum Tic-Tac-Toe.
Here is the setup for a puzzle where X has real marks in
three corners, O has two real marks elsewhere, and it
is her move. Can she defeat X?
| Move | | X | | O |
| 1 | | 1 - 9 | | 1 >9 |
| 3 | | 3 - 6 | | 6 - 7 |
| 5 | | 7< 3 | | |
| 7 | | | | |
| 9 | | | | |
Here is another setup that is more realistic;
X has real marks in squares 1, 3 and 7, and
O has real marks in squares 5, 8 and 9.
O has already blocked one of X's possible wins
by taking the middle square, but it is X's move.
Now can she defeat X?
| Move | | X | | O |
| 1 | | 1 - 3 | | 5 - 9 |
| 3 | | 1< 3 | | 5 >9 |
| 5 | | 7 - 8 | | 7 >8 |
| 7 | | | | |
| 9 | | | | |
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