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Last month, we looked at how rapidly the game tree branches in Quantum Tic-Tac-Toe,
and considered how to keep the number of branches small. The obvious way is to
"prune early, prune often." The extremum of that strategy is for player O to match X's every
move, forcing a collapse every pair of moves. Can X win if O does that?
The answer is, of course X can win, because he gets to pick all the collapses.
O has granted X the right to pick every one of her moves!
Consider this example game:
| Move | | X | | O |
| 1 | | 1 - 6 | | 6 < 1 |
| 3 | | 3 - 8 | | 8 < 3 |
| 5 | | 9 - 4 | | 4 < 9 |
| 7 | | 7 - 2 | | 2 < 7 |
| 9 | | 5 < 5 | | |
X plays in squares 1 and 6, O plays in the same squares,
and X chooses that O really moved in square 6 (the direction of the arrow
shows which ghost mark becomes real), giving himself a real mark in square 1.
He continues and she replies in kind, until X has all four corners.
The last move of the game is self-collapsing (since there is only one square
for both ghost moves to go into), and X has the center, and two points.
Of course, this example is too obvious, and O isn't going to fall for it.
She could play move eight in squares 2 and 5 instead of 2 and 7; this almost lets
her win (take a look at the ensemble of real games), but X can still win
by a half-point (what's his move?).
If she sees where the game is going a bit earlier, O could play
move six in squares 4 and 5, which gives her a shot at winning by a half-point.
X can defeat her still, but it's more difficult.
The cause of X's troubles is greed; he loses by wanting the two-point win.
His better choice would be squares 2 and 4 on move five; this guarantees him a 1-point
win, either on move six (if O continues her "mimic" strategy),
or on move seven (if she abandons it).
So, if O pursues the "mimic" strategy for even two moves, she loses.
It is an open question whether she can win if she collapses X's first move.
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